php发送post请求函数分享
2014-08-14来源:

代码如下:

function do_post_request($url, $data, $optional_headers = null)

{

 $params = array('http' => array(

'method' => 'post',

'content' => $data

 ));

 if ($optional_headers !== null) {

$params['http']['header'] = $optional_headers;

 }

 $ctx = stream_context_create($params);

 $fp = @fopen($url, 'rb', false, $ctx);

 if (!$fp) {

throw new exception(problem with $url, $php_errormsg);

 }

 $response = @stream_get_contents($fp);

 if ($response === false) {

throw new exception(problem reading data from $url, $php_errormsg);

 }

 return $response;

}

用法如下:

代码如下:

//json字符串

$data = {...};

//转换成数组

$data=json_decode($data,true);

$postdata = http_build_query($data);

do_post_request(http://localhost,$postdata);

更多信息请查看IT技术专栏

推荐信息
Baidu
map